若5x平方-4xy-y平方-x+1\4=0,求x、y的值
问题描述:
若5x平方-4xy-y平方-x+1\4=0,求x、y的值
如题
答
(2x-y)^2+(x-0.5)^2=0 x=0.5,y=1
若5x平方-4xy-y平方-x+1\4=0,求x、y的值
如题
(2x-y)^2+(x-0.5)^2=0 x=0.5,y=1