比较大小tan12π/5与tan(-16/3π)
问题描述:
比较大小tan12π/5与tan(-16/3π)
答
tan12π/5
=tan(12π/5-2π)
=tan(2π/5)>0
tan(-16/3π)
=tan(-16π/3+3π)
=tan(-π/3)
=-tanπ/3tan(-16/3π)