y=x^2(1-x^2)的最大值(0
问题描述：
y=x^2(1-x^2)的最大值(0
数学人气：640 ℃时间：2020-07-23 06:12:52
优质解答
y=x^2(1-x^2)=-(x^4-x^2+1/4)+1/4=-(x^2-1/2)^2+1/4
答
y=x^2(1-x^2)=-(x^4-x^2+1/4)+1/4=-(x^2-1/2)^2+1/4