函数y=sin(x+π/2)单调区间

问题描述:

函数y=sin(x+π/2)单调区间

y=sin(x+π/2)
=cosx
所以
x∈【2Kπ,2kπ+π】单调递减
x∈【2kπ+π,2Kπ+2π】单调递增.