∫1/√(a^2-x^2)^3dx(a>0)
问题描述：
∫1/√(a^2-x^2)^3dx(a>0)
答
∫1/√(a²-x²)³dx令x=asinu,则√(a²-x²)=acosu,dx=acosudu=∫1/(a³cos³u) *acosudu=(1/a²)∫sec²udu=(1/a²)tanu+C由x=asinu,则√(a²-x²)=acosu,得：ta...