e^(-t)sin(t/2) 求导
问题描述:
e^(-t)sin(t/2) 求导
答
[e^(-t)sin(t/2)]'
=[e^(-t)]'sin(t/2)+e^(-t)[sin(t/2)]'
=-e^(-t)sin(t/2)+e^(-t)[1/2*cos(t/2)]
=e^(-t)[1/2*cos(t/2)-sin(t/2)]