函数y=xcos2x在点(π/4,0)处的切线方程是

问题描述:

函数y=xcos2x在点(π/4,0)处的切线方程是

y'=cos2x=2xsinx
y'i=π/4=-(根号2)×π/4
4π(根号2)x+16y+π^2(根号2)=0