(x^4/3-y^4/3)/(x^2/3+y^2/3)=?2.4^x_4^(x-1)=24 求x=?
问题描述:
(x^4/3-y^4/3)/(x^2/3+y^2/3)=?2.4^x_4^(x-1)=24 求x=?
答
1、 (x^4/3-y^4/3)= (x^2/3-y^2/3)* (x^2/3+y^2/3)所以 (x^4/3-y^4/3)/(x^2/3+y^2/3)=(x^2/3-y^2/3)* (x^2/3+y^2/3)/(x^2/3+y^2/3)=(x^2/3-y^2/3)2、4^x-4^(x-1)=244^x-1/4*4^x=24 3/4*4^x=24 解得 x=2....