设复数z=√2(cosπ/6+isinπ/6),则z^2=?
问题描述:
设复数z=√2(cosπ/6+isinπ/6),则z^2=?
答
z²=(√2)²(cos2*π/6+isin2*π/6)
=2(1/2+i√3/2)
=1+i√3