(1+根号2)乘以x的平方-(1-根号2)乘以X=0怎么解
问题描述：
(1+根号2)乘以x的平方-(1-根号2)乘以X=0怎么解
答
(1+√2)x^2-(1-√2)x=0
化简得，x[(1+√2)x-(1-√2)]=0
即x=0或x=(1-√2)/(1+√2）
所以方程的解为x=0或x=(1-√2)/(1+√2）=2√2-3 （(1-√2)(1+√2）=-1）
答
(1+√2)x^2-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
x=0或x=(1-√2)/(1+√2)=-(1-√2)^2=2√2-3
x=0或x=2√2-3