若-x^2y=2,则-xy{x^5y^2-x^3y+2x}的值为多少

问题描述:

若-x^2y=2,则-xy{x^5y^2-x^3y+2x}的值为多少

原式=-x^6y^4+x^4y²-2x²y
=-(x²y)³+(x²y)²-2x²y
=-8+4-4
=-8

-x^2y=2
x^2y=-2
-xy{x^5y^2-x^3y+2x}
=-x^6y^3+x^4y^2-2x^2y
=-(x^2y)^3+(x^2y)^2-2x^2y
=8+4+4
=16