解一元二次5x^2-18x=9x

问题描述:

解一元二次5x^2-18x=9x

5x^2-18x=9x
5x²-27x=0
x(5x-27)=0
x=0 5x-27=0
∴x1=0
x2=5.4

5x^2-27x=0
x(5x-27)=0
x=0 or x=27/5