(3+1)(3二次+1)(3四次+1)...(3三十二次+1)-3六十四次/2
问题描述：
(3+1)(3二次+1)(3四次+1)...(3三十二次+1)-3六十四次/2
答
=(3-1)(3+1)(3^2+1)…………(3^32+1)/(3-1)-3^64/2
=(3^2-1)(3^2+1)……(3^32+1)/(3-1)-3^64/2
=(3^4-1)(3^4+1)…………
……
……
=3^64/2-3^64/2
=0
答
原式=2(3+1)(3二次+1)(3四次+1)...(3三十二次+1)/2-3六十四次/2 =(3-1)(3+1)(3二次+1)(3四次+1)...(3三十二次+1)/2-3六十四次/2 =(3二次-1)(3二次+1)(3四次+1)...(3三十二次+1)/2-3六十四次/2 =(3四次-1)(3四次+1).....