已知x²+y²=6,则代数式(3x²-2xy-y²)-(x²-2xy-3y²)的值为多少?
问题描述:
已知x²+y²=6,则代数式(3x²-2xy-y²)-(x²-2xy-3y²)的值为多少?
答
(3x²-2xy-y²)-(x²-2xy-3y²)=3x²-2xy-y²-x²+2xy+3y²=2x²+2y²=12
已知x²+y²=6,则代数式(3x²-2xy-y²)-(x²-2xy-3y²)的值为多少?
(3x²-2xy-y²)-(x²-2xy-3y²)=3x²-2xy-y²-x²+2xy+3y²=2x²+2y²=12