已知x²+y²=6,则代数式(3x²-2xy-y²)-(x²-2xy-3y²)的值为多少?

问题描述:

已知x²+y²=6,则代数式(3x²-2xy-y²)-(x²-2xy-3y²)的值为多少?

(3x²-2xy-y²)-(x²-2xy-3y²)=3x²-2xy-y²-x²+2xy+3y²=2x²+2y²=12