求不定积分x ∫(1-x^2)/x根号下x dx∫(1-x^2)/x*根号下x dx
问题描述:
求不定积分x ∫(1-x^2)/x根号下x dx
∫(1-x^2)/x*根号下x dx
答
∫(1-x^2)/x^(3/2) dx
=∫[x^(-3/2) - x^(1/2)] dx
= -2x^(1/2) - (2/3)x^(3/2) + c