使分子,分母各项系数的绝对值是最小整数,则分式(0.02x+0.06y)/(0.8x-0.2y)
问题描述:
使分子,分母各项系数的绝对值是最小整数,则分式(0.02x+0.06y)/(0.8x-0.2y)
答
(0.02x+0.06y)/(0.8x-0.2y)
=(2x+6y)/(80x-20y)
=(x+3y)/(40x-10y)