tan(-2010°)+cos(-79π/6)
问题描述:
tan(-2010°)+cos(-79π/6)
答
【1】tan(-2010º)=-tan2010º=-tan[6×360º-150]=tan150º=tan(180º-30º)=-tan30º=-(√3)/3【2】cos(-79π/6)=cos(79π/6)=cos[12π+(7π/6)]=cos(7π/6)=cos[π+(π/6)]=-cos(π/...