(tan60°-2tan45°)分之(2sin60°-1)
问题描述:
(tan60°-2tan45°)分之(2sin60°-1)
(tan60°-2tan45°)分之(2sin60°-1)
答
(2sin60°-1)/(tan60°-2tan45°)
=[2*(√3/2)-1]/(√3-2)
=(√3-1)/(√3-2)
=-(√3-1)(√3+2)/(-1) 【分母有理化】
=-3-2√3+√3+2
=-1-√3