a1=1,a2=6,sn=3sn-1-2sn-2+2^n(n大于等于3)求证:an/2^n是等差数列
问题描述:
a1=1,a2=6,sn=3sn-1-2sn-2+2^n(n大于等于3)求证:an/2^n是等差数列
答
a₁=1,a₂=6,S‹n›=3S‹n-1›-2S‹n-2›+2ⁿ(n大于等于3)求证:a‹n›/2ⁿ是等差数列证明:a‹n›=S‹n›-S‹n-1›...