若有理数(x+y+2)(x+y-1)=0,则x+y的值为

问题描述:

若有理数(x+y+2)(x+y-1)=0,则x+y的值为


(x+y+2)(x+y-1)=0

x+y+2=0
或x+y-1=0

x+y=-2
或x+y=1