(y+2)÷4-(2y-3)÷6=1 求y的值

问题描述:

(y+2)÷4-(2y-3)÷6=1 求y的值

(y+2)÷4-(2y-3)÷6=1
(y+2)/4-(2y-3)/6=1
(6y+8)/24-(8y-12)/24=1
(6y+8-8y+12)/24=1
6y-8y+20=24
-2y=4
y=-2y不是等于0吗不好意思,算错了,好多年没动笔了y到底得多少啊拜托准确率高一点多谢(3y+6-4y+6)/12=112-y=12y=0