tan(-35π/6)·sin(-46π/3)-cos(37π/6)·tan(55π/6)=?
问题描述：
tan(-35π/6)·sin(-46π/3)-cos(37π/6)·tan(55π/6)=?
要过程
答
原式=tan(π/6-6π)·sin(2π/3-16π)-cos(π/6+6π)·tan(π/6+6π)
=tan(π/6)·sin(2π/3)-cos(π/6)·tan(π/6)
=tan(π/6)·sin(π/3)-cos(π/6)·tan(π/6)
=tan(π/6)·cos(π/6)-cos(π/6)·tan(π/6)
=0