4.计算∫√[1+p/(2t)]dt
问题描述：
4.计算∫√[1+p/(2t)]dt
答
令sqrt(1+p/(2t))=y
则dt=-py/(y^2-1)^2
积分下限正无穷
上限sqrt(1+p/(2x))
原试可化简为-∫[p(1/(y^2-1)+1/(y^2-1)^2]dy
下面的你自己来吧