x^+2x+1+y^2-8y+16=0求y/x
问题描述：
x^+2x+1+y^2-8y+16=0求y/x
答
∵x^2+2x+1+y^2-8y+16 =(x+1)^2+(y-4)^2=0 ∴x=-1 y=4(两非负数和为0则必须两个同时为0) ∴y/x=-4
x^+2x+1+y^2-8y+16=0求y/x
∵x^2+2x+1+y^2-8y+16 =(x+1)^2+(y-4)^2=0 ∴x=-1 y=4(两非负数和为0则必须两个同时为0) ∴y/x=-4