如图,已知直线AB,CD交于点O,OE平分∠AOD,OF平分∠AOC,求证OE⊥OF
问题描述:
如图,已知直线AB,CD交于点O,OE平分∠AOD,OF平分∠AOC,求证OE⊥OF
答
由已知可得:角AOD+角AOC=180度,则1/2角AOC+1/2角AOD=1/2(角AOC+角AOD)=90度…故OF与OE垂直
如图,已知直线AB,CD交于点O,OE平分∠AOD,OF平分∠AOC,求证OE⊥OF
由已知可得:角AOD+角AOC=180度,则1/2角AOC+1/2角AOD=1/2(角AOC+角AOD)=90度…故OF与OE垂直