(y-1)^2+2y(1-y)=0因式分解发,

分类: 作业答案 • 2022-03-28 19:20:11

问题描述：

答

(y-1)^2+2y(1-y)=0
(y-1)^2-2y(y-1)=0
(y-1)[(y-1)-2y]=0
(y-1)(-1-y)=0
(y-1)(y+1)=0
y=1或y=-1