x6-y6+x4+x2y2+y4因式分解x10+x5-2

分类: 作业答案 • 2022-03-27 23:26:33

问题描述：

答

x6-y6+x4+x2y2+y4
=(x2-y2)(x4+x2y2+y4)+(x4+x2y2+y4)
=(x2-y2+1)(x4+x2y2+y4)
x10+x5-2
=(x5-1)(x5+2)
=(x-1)(x4+x3+x2+x+1)(x5+2)