若x/x2−x−2=a/x+1+b/x−2(a、b为常数),则a=_,b=_.
问题描述:
若
=x
x2−x−2
+a x+1
(a、b为常数),则a=______,b=______. b x−2
答
∵
=x
x2−x−2
+a x+1
,b x−2
∴
=x
x2−x−2
+a(x−2)
x2−x−2
,b(x+1)
x2−x−2
∴x=(a+b)x-2a+b,
∴a+b=1,-2a+b=0,
解得a=
,b=1 3
.2 3
故答案为
,1 3
.2 3