已知(x-15)2=169,(y-1)3=-0.125,求x−2xy−32y−x的值.

问题描述:

已知(x-15)2=169,(y-1)3=-0.125,求

x
2xy
3 2yx
的值.

∵(x-15)2=169,(y-1)3=-0.125,∴x-15=±13,y-1=-0.5,∴x=28或x=2,y=0.5,当x=28,y=0.5时,原式=28-2×28×0.5-32×0.5-28=27-27+3=3;当x=2,y=0.5时,原式=2-2×2×0.5-32×0.5-2=2-2+1=1....