求证sin^4x-cos^4x=sin^2x-cos^2x
问题描述:
求证sin^4x-cos^4x=sin^2x-cos^2x
答
sin^4x-cos^4x =(sin^2x+cos^2x)(sin^2x-cos^2x)
∵sin^2x+cos^2x=1
∴sin^4x-cos^4x =(sin^2x+cos^2x)(sin^2x-cos^2x)=(sin^2x-cos^2x)