1、(x^2+x+1)/(x^2+1)+(2x^2+x+2)/(x^2+x+1)=19/6
问题描述：
1、(x^2+x+1)/(x^2+1)+(2x^2+x+2)/(x^2+x+1)=19/6
2、关于x的方程：x+1/（x-1）=a+1/(a-1) (a≠1)
3、(3/x+5)(3/x+7)=48-4(x-3)^2
答
对不起,是x的平方再乘2?（2）x+1/x-1=a+1/a-1原方程可化为(x+1)(a-1)/(x-1)(a-1)=(a+1)(x-1)/(a-1)(x-1)所以(x+1)(a-1)/(x-1)(a-1)-(a+1)(x-1)/(a-1)(x-1)=0化简,得2(a-x)/(x-1)(a-1)=0两边同乘(x-1)(a-1)2a-2x=0x=a...