计算:(6/5)^3÷(5/6)^-3+(-3/2)^2÷(2/3)^13-(1/3-3)^0+3^-1

问题描述:

计算:(6/5)^3÷(5/6)^-3+(-3/2)^2÷(2/3)^13-(1/3-3)^0+3^-1
:不好意思 正确的:(6/5)^3÷(5/6)^-3+(-3/2)^2÷(2/3)^-3-(1/3-3)^0+3^-1

(6/5)^3÷(5/6)^-3+(-3/2)^2÷(2/3)^13-(1/3-3)^0+3^-1
=(6/5)^3(6/5)^-3+(-3/2)^2(3/2)^13-1-1
=(6/5)^(3-3)+(-1)^2(3/2)^(2+13)-1-1
=1+(3/2)^15-1-1
=(3/2)^15-1

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谢谢答案上是1哎(6/5)^3÷(5/6)^-3+(-3/2)^2÷(2/3)^13-(1/3-3)^0+3^-1=(6/5)^3(6/5)^-3+(-3/2)^2(3/2)^13-1+1/3=(6/5)^(3-3)+(-1)^2(3/2)^(2+13)-1+1/3=1+(3/2)^15-1+1/3=(3/2)^15-1/3太不好意思了 题目抄错了 正确的:(6/5)^3÷(5/6)^-3+(-3/2)^2÷(2/3)^-3-(1/3-3)^0+3^-1(6/5)^3÷(5/6)^-3+(-3/2)^2÷(2/3)^-3-(1/3-3)^0+3^-1=(6/5)^3(6/5)^-3+(-3/2)^2(3/2)^-3-1+1/3=(6/5)^(3-3)+(-1)^2(3/2)^(2-3)-1+1/3=(6/5)^0+(3/2)^(-1)-1+1/3=1+2/3-1+1/3=1