x÷(x-1)-1=3÷(x²+x-2) 和 x÷(x²-40)+2÷(x+2)=1÷(x-2)

问题描述:

x÷(x-1)-1=3÷(x²+x-2) 和 x÷(x²-40)+2÷(x+2)=1÷(x-2)

x÷(x-1)-1=3÷(x²+x-2) 两边乘以(x+2)(x-1)得x(x+2)-(x-1)(x+2)=3x²+2x-x²-x+2=3x=1检验:x=1是增根x÷(x²-4)+2÷(x+2)=1÷(x-2)两边乘以(x+2)(x-2)得x+2(x-2)=x+2x+2x-4=x+22x=6x=3...