计算(1)(0.25)1/2−[−2×(3/7)0]2×[(−2)3]4/3+(2−1)−1−21/2(2)1/2lg32/49−4/3lg8+lg245+(lg2)•lg50+lg25.

问题描述:

计算
(1)(0.25)

1
2
−[−2×(
3
7
)0]2×[(−2)3]
4
3
+(
2
−1)−12
1
2

(2)
1
2
lg
32
49
4
3
lg
8
+lg
245
+(lg2)•lg50+lg25

(1)原式=[(

1
2
)2]
1
2
-(-2)2+(-2)4+
1
2
-1
-
2
=
1
2
-4+16+
2
+1-
2
=
27
2

(2)原式=lg(
32
49
×
245
)
-lg(2
3
2
)
4
3
+lg2(1+lg5)+lg25
=lg(4
10
)
-2lg2+lg2+lg5(lg2+lg5)
=2lg2+
1
2
-2lg2+lg2+lg5
=
1
2
+1=
3
2