请计算 (a-b)的2n+1次方乘以(b-a)的2n-1次方
问题描述:
请计算 (a-b)的2n+1次方乘以(b-a)的2n-1次方
答
(a-b) 2n+1×(b-a) 2n-1
=(a-b) 2n+1×[-(a - b)] 2n-1
=-(a - b) 2n+1+2n-1
=-(a - b) 4n
请计算 (a-b)的2n+1次方乘以(b-a)的2n-1次方
(a-b) 2n+1×(b-a) 2n-1
=(a-b) 2n+1×[-(a - b)] 2n-1
=-(a - b) 2n+1+2n-1
=-(a - b) 4n