(a-4)^4+(a+b)^4+(a^2-b^2)^2因式分解

问题描述:

(a-4)^4+(a+b)^4+(a^2-b^2)^2因式分解
快回答啊 急

原式=(a-b)^4+2(a²-b²)²+(a+b)^4-(a²-b²)²
=(a-b)^4+2(a-b)²(a+b)²+(a+b)^4-(a²-b²)²
=[(a-b)²-(a+b)²]²-(a²-b²)²
=(a²-2ab+b²-a²-2ab+b²)²-(a²-b²)²
=(4ab)²-(a²-b²)²
=(2ab+a²-b²)(2ab-a²+b²)