已知tanx=2,tany=3,x,y∈(0,π/2),求x+y.
问题描述:
已知tanx=2,tany=3,x,y∈(0,π/2),求x+y.
答
tan(x+y)
=(tanx+tany)/(1-tanxtany)
=-1
x+y=3π/4