(1)√48÷√3-√1\2×√12+√24 (2)√0.5+√12-(√1\3-√4又1\2)

问题描述:

(1)√48÷√3-√1\2×√12+√24 (2)√0.5+√12-(√1\3-√4又1\2)

(1)√48÷√3-√1\2×√12+√24
=4-√2/2*2√2+2√6
=4-2+2√6
=2+2√6
(2)√0.5+√12-(√1\3-√4又1\2)
=√2/2+2 √3- (√3/3-3√2/2)
=2√2+5/3*√3 .