已知x=10,求x2-8x+16+9-6x+x2的值.

问题描述:

已知x=

10
,求
x2-8x+16
+
9-6x+x2
的值.

x2-8x+16
+
9-6x+x2

=
(x-4)2
+
(3-x)2

=
(
10
-4)2
+
(3-
10
)2

=4-
10
+
10
-3

=1.