化简:sin(-4π/3)cos(-23π/6)tan25π/4
问题描述:
化简:sin(-4π/3)cos(-23π/6)tan25π/4
答
sin(-4π/3)cos(-23π/6)tan25π/4
=sin(2π-4π/3)cos(4π-23π/6)tan(25π/4-6π)
=sin(2π/3)cos(π/6)tan(π/4)
=√3/2*√3/2*1
=3/4