(mn+1)^2-(mn-1)^2等于多少?
问题描述:
(mn+1)^2-(mn-1)^2等于多少?
答
原式=[(mn+1)(mn+1)]-[(mn-1)(mn-1)]
=m^2n^2+2mn+1-m^2n^2+2mn-1
=4mn