化简:1/(m-n)根号(m^3-2m^2n+mn^2)(m

问题描述:

化简:1/(m-n)根号(m^3-2m^2n+mn^2)(m

1/(m-n)根号(m^3-2m^2n+mn^2)
=1/(m-n)根号【m(m-n)^2】
=-根号m

1/(m-n)根(m³-2m²n+mn²)=1/(m-n)根【m(m²-2mn+n²)】=1/(m-n)根【m(m-n)²】=|m-n|/(m-n)根m.因为m<n,所以原式=-(m-n)/(m-n)根m=-根m.