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计算：1/x(x+2)+1/(x+1)(x+3)+1/(x+2)(x+4).+1/(x+2007)(x+2009)

分类: 作业答案 • 2022-03-13 13:17:34
问题描述：

计算：1/x(x+2)+1/(x+1)(x+3)+1/(x+2)(x+4).+1/(x+2007)(x+2009)

答

1/x(x+2)+1/(x+1)(x+3)+1/(x+2)(x+4).+1/(x+2007)(x+2009)=1/2[2/x(x+2)+2/(x+1)(x+3)+2/(x+2)(x+4).+2/(x+2007)(x+2009)]=1/2[1/x-1/(x+2)+1/(x+1)-1/(x+3)+1/(x+2)-1/(x+4).+1/(x+2007)-1/(x+2009)]=1/2[1/x+1/(x+...

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