若x^2-6x+4y^2+4y+10=0,则x^2+y^2=
问题描述:
若x^2-6x+4y^2+4y+10=0,则x^2+y^2=
x^2-6x+4y^2+4y+10=0,
x^2+y^2=
答
x^2-6x+4y^2+4y+10=0,
(x-3)^2+(2y+1)^2=0,
x=3,y=-1/2,
x^2+y^2=37/4.