计算: (1)x+2/x2-2x-x-1/x2-4x+4; (2)x2x-1-x-1.
问题描述:
计算:
(1)
-x+2
x2-2x
; x-1
x2-4x+4
(2)
-x-1. x2 x-1
答
(1)原式=
-
x2-4 x(x-2)2
=x(x-1) x(x-2)2
;x-4 x(x-2)2
(2)原式=
=
x2-(x+1)(x-1) x-1
.1 x-1