计算: (1)x+2/x2-2x-x-1/x2-4x+4; (2)x2x-1-x-1.

问题描述:

计算:
(1)

x+2
x2-2x
-
x-1
x2-4x+4
;            
(2)
x2
x-1
-x-1

(1)原式=

x2-4
x(x-2)2
-
x(x-1)
x(x-2)2
=
x-4
x(x-2)2

(2)原式=
x2-(x+1)(x-1)
x-1
=
1
x-1