已知函数f(x)=2√3sinxcosx+cos^2x-sin^2x-1

问题描述:

已知函数f(x)=2√3sinxcosx+cos^2x-sin^2x-1
求周期和递增区间

f(x)=2√3sinxcosx+cos^2x-sin^2x-1
f(x)=√3sin2x+cos2x-1
=sin(2x+π/6)-1
所以周期为:T=2π/w=π.