若x2+x-1=0,则x3+2x2-7=_.

问题描述:

若x2+x-1=0,则x3+2x2-7=___

∵x2+x-1=0,
∴x2+x=1,
∴x3+2x2-7
=x(x2+x)+x2-7
=x2+x-7
=1-7
=-6.
故答案为:-6.