圆c1;x^2+y^2+2mx+4y+m^2-5=0,圆c2;x^2+y^2-2x-2my+m^2-3=0(m>0),(1若外切,求出m的值及俩圆外公切线
问题描述:
圆c1;x^2+y^2+2mx+4y+m^2-5=0,圆c2;x^2+y^2-2x-2my+m^2-3=0(m>0),(1若外切,求出m的值及俩圆外公切线
答
圆C1:x²+y²+2mx+4y+m²-5=0,圆C2:x²+y²-2x-2my+m²-3=0,(m>0)相切,即圆心距离为两圆半径之和:圆C1:x²+y²+2mx+4y+m²-5=0x²+2mx+m²+y²+4y+4=9(x+m)...