利用等式（a+b）/ab=1/a+1/b,化简(2√2+√3+1)/(√6+√3+√2+2)

分类: 作业答案 • 2022-03-07 10:38:14

问题描述：

答

(2√2+√3+1)/(√6+√3+√2+2)
=(2√2+√3+1)/[√2(√3+√2)+(√3+√2)]
=[(√3+√2)+(√2+1)]/[(√3+√2)(√2+1)]
=1/[(√3+√2)]+1/[(√2+1)]
=[(√3-√2)+[(√2-1)]
=√3-1