(2分之3a^n+3 -2a^n+1)÷(-3分之1a^n-1) 计算

问题描述:

(2分之3a^n+3 -2a^n+1)÷(-3分之1a^n-1) 计算

(2分之3a^n+3 -2a^n+1)÷(-3分之1a^n-1)
=2分之3a^n+3 ÷(-3分之1a^n-1)-2a^n+1 ÷(-3分之1a^n-1)
=-2a的4次方+6a²